- Factorise fully $6x^2-7x-20 = (3x+4)(2x-5)$
[2 marks]
- Complete the square: \[ y=5-2x-3x^2 = -3(x+\frac{1}{3})^2 + \frac{16}{3} \]
Has max at (-1/3 , 16/3)
y intercept is 5
x intercepts are -5/3 and 1[4 marks]
- Sketch $y=(3-x)(2x+5)^2$ indicating any intersections with the axes
y intercept is 75
cross at x=3 with touch x=-5/2
negative cubic shape[4 marks]
- \[ y^2=x^2+x \\ y=2x+k \\ 4x^2+4kx+k^2 = x^2+x \\ 3x^2+x(4k-1)+k^2=0 \\ \therefore (4k-1)^2-12k^2<0 \\4k^2-8k+1<0
\\ \frac{2-\sqrt 3}{2} < k < \frac{2+\sqrt 3}{2}
\]Find the values of k such that the hyperbola and the line do not meet.
[4 marks]
- Find the centre and radius of the circle that passes through A(9,3), B(13,-5) and C(-5,-11) \[ (x-3)^2 + (y+5)^2 = 100 \]
[5 marks]
- Solve: \[ \frac{3}{27^{5-x}}=\sqrt{81^{5-2x}} \\ \\ 3^{1-3(5-x)}=3^{\frac{4(5-2x)}{2}} \\ \\ 1-15+3x=10-4x \\ x= \frac{24}{7}\]
[3 marks]
- Simplify as far as possible: \[ \frac{15}{\sqrt 5} - \frac{6}{\sqrt 7 - \sqrt 5} = -3\sqrt 7 \]
[3 marks]
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Monday, 5 October 2015
6.6 FM Progress answers 5.10.15
Total: 25 marks. Show all working out. Those not showing mathematical rigour will be penalised.
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